(1x^2+16x-21)/(2x-1)

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Solution for (1x^2+16x-21)/(2x-1) equation: 


D( x )

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

(1*x^2+16*x-21)/(2*x-1) = 0

(x^2+16*x-21)/(2*x-1) = 0

x^2+16*x-21 = 0

x^2+16*x-21 = 0

DELTA = 16^2-(-21*1*4)

DELTA = 340

DELTA > 0

x = (340^(1/2)-16)/(1*2) or x = (-340^(1/2)-16)/(1*2)

x = (2*85^(1/2)-16)/2 or x = (-2*85^(1/2)-16)/2

(x-((-2*85^(1/2)-16)/2))*(x-((2*85^(1/2)-16)/2)) = 0

((x-((-2*85^(1/2)-16)/2))*(x-((2*85^(1/2)-16)/2)))/(2*x-1) = 0

( x-((-2*85^(1/2)-16)/2) )

x-((-2*85^(1/2)-16)/2) = 0 // + (-2*85^(1/2)-16)/2

x = (-2*85^(1/2)-16)/2

( x-((2*85^(1/2)-16)/2) )

x-((2*85^(1/2)-16)/2) = 0 // + (2*85^(1/2)-16)/2

x = (2*85^(1/2)-16)/2

x in { (-2*85^(1/2)-16)/2, (2*85^(1/2)-16)/2 }

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